🏐 5 X2 1 4 X2 1 Você está absolutamente certo. Nesse algo eu gosto dessa ideia, concordo plenamente com você.

For example, the function x2 x 2 takes the reals (domain) to the non-negative reals (range). The sine function takes the reals (domain) to the closed interval [−1,1] [ − 1, 1] (range). (Both of these functions can be extended so that their domains are the complex numbers, and the ranges change as well.) Domain and Range Calculator: Wolfram 5x2-4x-1 Final result : (x - 1) • (5x + 1) Step by step solution : Step 1 :Equation at the end of step 1 : (5x2 - 4x) - 1 Step 2 :Trying to factor by splitting the middle term x2-4x-12 Final result : (x + 2) • (x - 6) Step by step solution : Step 1 :Trying to factor by splitting the middle term 1.1 Factoring x2-4x-12 The first term is y = x2 − 1 y = x 2 - 1. Find the properties of the given parabola. Tap for more steps Direction: Opens Up. Vertex: (0,−1) ( 0, - 1) Focus: (0,−3 4) ( 0, - 3 4) Axis of Symmetry: x = 0 x = 0. Directrix: y = −5 4 y = - 5 4. Select a few x x values, and plug them into the equation to find the corresponding y y values. Algebra. Simplify 4 (x-2) 4(x − 2) 4 ( x - 2) Apply the distributive property. 4x+4⋅−2 4 x + 4 ⋅ - 2. Multiply 4 4 by −2 - 2. 4x−8 4 x - 8. Free math problem solver answers your algebra, geometry, trigonometry, calculus, and statistics homework questions with step-by-step explanations, just like a math tutor. Algebra and Trigonometry (MindTap Course List) Algebra. ISBN: 9781305071742. Author: James Stewart, Lothar Redlin, Saleem Watson. Publisher: Cengage Learning. SEE MORE TEXTBOOKS. Solution for (x - 1)4 - 5 (x - 1)2 + 4 = 0. Algebra. Solve for x x^2+1=0. x2 + 1 = 0 x 2 + 1 = 0. Subtract 1 1 from both sides of the equation. x2 = −1 x 2 = - 1. Take the specified root of both sides of the equation to eliminate the exponent on the left side. x = ±√−1 x = ± - 1. Solve Using the Quadratic Formula x^2-x+1=0. x2 − x + 1 = 0 x 2 - x + 1 = 0. Use the quadratic formula to find the solutions. −b±√b2 −4(ac) 2a - b ± b 2 - 4 ( a c) 2 a. Substitute the values a = 1 a = 1, b = −1 b = - 1, and c = 1 c = 1 into the quadratic formula and solve for x x. 1±√(−1)2 − 4⋅(1⋅1) 2⋅1 1 ± ( - 1) 2 We have to find the value of. x2+ 1 x2. = (9−4√5)2+(9+4√5)2 [Using equation (i) and (ii)] = [92+(4√5)2−2×9×4√5]+[92+(4√5)2+2×9×4√5) [ ∵ (a±b)2 = a2+b2−±2ab ] = [81+80−72√5]+[81+80+72√5] = 161−72√5+161+72√5 = 322. Suggest Corrections. 235. Simplify and combine like terms. Tap for more steps (x2 − 6x+8)(x−1) ( x 2 - 6 x + 8) ( x - 1) Expand (x2 −6x +8)(x−1) ( x 2 - 6 x + 8) ( x - 1) by multiplying each term in the first expression by each term in the second expression. x2x+ x2 ⋅−1− 6x⋅x−6x⋅−1+ 8x+8⋅−1 x 2 x + x 2 ⋅ - 1 - 6 x ⋅ x - 6 x ⋅ - 1 + 8 x Highlights. Actual Dimensions: 1/4 in. thickness x 1-1/2 in. width x 4 ft. length. Surfaced 4 sides, ready for paint or stain. Recommended for interior use, may be used for carpentry, hobbies, furniture, shelving and general finish work. Each piece of this lumber meets the highest quality grading standards for strength and appearance. 4 (x+1)2-28 (x+1)+49 Final result : (2x - 5)2 Step by step solution : Step 1 :Equation at the end of step 1 : ( (4• ( (x+1)2))-28• (x+1))+49 Step 2 :Equation at the end of step 2 : (4 • (x + 1)2 - x2-2x+1= (298096/100) Two solutions were found : x = -53.59817 x = 55.59817 Reformatting the input : Changes made to your input should not Therefore, ∫ dx x2 +1 = ∫ sec2θdθ sec2θ = ∫dθ = θ = arctan(x) Putting it all together. ∫ x4dx x2 +1 = x3 3 − x + arctan(x) + C. Answer link. The answer is =x^3/3-x+arctan (x)+C We need intx^ndx=x^ (n+1)/ (n+1)+C (n!=-1) We perform a polynomial long division color (white) (aaaa)x^4color (white) (aaaaaaaaa)∣x^2+1 color (white Click here 👆 to get an answer to your question ️ Factor completely 4x2 − 8x + 4. A Prime B 4x(x2 − 2x + 1) C 4(x2 − 2x + 1) D 4(x2 + 4) Simplify (x^2+1)/ (x^2-1) x2 + 1 x2 − 1 x 2 + 1 x 2 - 1. Rewrite 1 1 as 12 1 2. x2 +1 x2 −12 x 2 + 1 x 2 - 1 2. Since both terms are perfect squares, factor using the difference of squares formula, a2 −b2 = (a+b)(a−b) a 2 - b 2 = ( a + b) ( a - b) where a = x a = x and b = 1 b = 1. x2 +1 (x+1)(x−1) x 2 + 1 ( x + 1) ( x - 1) The solution (s) to a quadratic equation can be calculated using the Quadratic Formula: The "±" means we need to do a plus AND a minus, so there are normally TWO solutions ! The blue part ( b2 - 4ac) is called the "discriminant", because it can "discriminate" between the possible types of answer: when it is negative we get complex solutions. .

5 x2 1 4 x2 1