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Solve for t: |2t+6|=4 The solution is t=-5\lor t=-1 Study Tools AI Math Solver Popular Problems Study Guides Practice Cheat Sheets Calculators Graphing Calculator Geometry Calculator 55" Class TU690T Crystal UHD 4K Smart TV powered by Tizen™. UN55TU690TFXZA. Total $299.99 $379.99 Samsung Financing $12.50/mo $15.83/mo for 24 mos⊕. Notify me. Benefits. This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. Question: Consider the line L (t) = <-1-2t, 3 - 5t>. Then L intersects: The x-axis at the point when t =. The y - axis at the point when t =. The parabola y = x^2 at the points and when t = and . By breaking the polynomial into groups of three terms and completing the square, we get: \begin{align} & \hspace{0.36 in} t^6-t^5+t^4-t^3+t^2-t+\dfrac{2}{5} \\ &= See a solution process below: Explanation: To find g(h(t)) we must substitute (h(t)) or (2t) The polynomial f (T)= T 3 +2T +1 is irreducible over F3 because it has no roots (and has degree 3 ). We can always build an extension field where f has a root, namely K = F3[T]/(f (T))= F3[α] Application of consecutive chain rules. Q: f'(t) = 6t2 + 2t - 4 A: Given: f't=6t2+2t-4 for finding solution of given differential equation, we use variable separable… Q: 6. f(t) = e-5t(5 + t³) %3D Y (x, t) = 0.05 (4 x + 2 t) 2 + 5 The general equation for a wave is given by f (ω t − k x) = Y (x, t); Comparing with the given equation we get ω = 2 r a d s − 1 and k = − 4 m − 1 v = ω k v = − 0.5 m s − 1 (negative sign indicates travel in negative x direction) The function obtains maximum displacement when (4 x + 2 t) vanishes Let → r ( t ) = < − 5 t 4 + 1 , t 5 − 2 t 3 , 3 ln ( 3 t ) > Find a parametric equation of the line tangent to → r ( t ) at the point ( − 404 , 189 , 6.592 ) This problem has been solved! You'll get a detailed solution from a subject matter expert that helps you learn core concepts. You can put this solution on YOUR website!-4t-5>2t+13 +5 +5 Add five to both sides. -4t>2t+18-2t -2t Subtract 2t. -6t>18 Divide by -6. The inequality sign flips because you're dividing by a negative number. This gives you a system of 3 equations, which you can use any two of to solve (If there is a solution. There's no guarantee that two lines will intersect! You'll have to check your results to make sure both lines completely meet.) -2t = -9 + 5s. 1 + 2t = 5s. 3t = 2 + 4s. Adding the first two equations makes it easy to solve for s. Answer: Value of t = 7. Step-by-step explanation: Given simple equation: t-(2t+5)-5(1-2t)=2(3+4t)-3(t-4)=> t-2t-5-5 + 10t = 6 + 8t-3t + 12 => t-2t + 10t-8t + 3t = 6 How do you solve 2(v + 2) = 3v + 3 ? v =1 Explanation: 2(v +2) =3v+3 First distribute the terms on the left side: 2v +4 = 3v +3 Isolate v by 4 (h+2)=3 (h-2) One solution was found : h = -14 Rearrange: Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : Algebra. Solve for t 6t=3 (t+4)-t. 6t = 3 (t + 4) − t 6 t = 3 ( t + 4) - t. Since t t is on the right side of the equation, switch the sides so it is on the left side of the equation. 3(t+4)− t = 6t 3 ( t + 4) - t = 6 t. Simplify 3(t+4)−t 3 ( t + 4) - t. Tap for more steps 2t+12 = 6t 2 t + 12 = 6 t. Move all terms containing t t to the You'll get a detailed solution from a subject matter expert that helps you learn core concepts. Question: Find the distance of the point (4,6,−4) from the line r (t)=<1+2t,1+3t,7−2t>. Answer: ____________. Find the distance of the point (4,6,−4) from the line r (t)=<1+2t,1+3t,7−2t>. There are 2 steps to solve this one. Two numbers r and s sum up to \frac{3}{2} exactly when the average of the two numbers is \frac{1}{2}*\frac{3}{2} = \frac{3}{4}. You can also see that the midpoint of r and s corresponds to the axis of symmetry of the parabola represented by the quadratic equation y=x^2+Bx+C. .

6 4 t 55 5 2t 3